SUBNETING EXAMPLES

Q, 192.168.1.0 /25

ANS :

1. SUBNET

2. CIDR

3. NO: OF NETWORKS

4. NO OF HOSTS

STEP 1:

SUBNET

HERE IN QUESTIONIT IS GIVEN THAT THE CIDR IS 25

SO PUT 25 ONES OUT OF 32 BIT S AND THE REST WITH ZEROS

11111111 . 11111111 . 11111111 . 10000000

CONVERT IT INTO BINARY

128+64+32+16+8+4+2+1  . 128+64+32+16+8+4+2+1 . 128+64+32+16+8+4+2+1 . 128+0+0+0+0+0+0+0

255 . 255 . 255 . 128

SO THE SUBNET IS 255.255.255.128

STEP 2;

CIDR

IN THE QUESTION ITSELF IT IS GIVEN THAT THE CISR IS 25

CIDR = 25

 STEP :3

NO:NETWORKS 

                                   = 2^N

                                   = 2 (^{NO: OF ONE IN HOST PORTION OF CIDR’S BINARY VALUE)}

                                    = 2¹

                                                       = 2NETWORKS

 STEP 4:

NO OF HOSTS

                   = 2^N – 2

                   = 2 ^{(NUMBER OF ZEROS IN HOST PORTION OF BINARY VALUE OF CIDR)}- 2

                   =2 ⁷-2

                   =128-2

                   =126 HOST IN EACH NETWORK

HERE COMPUTER WITH THE IP ADDRESS NETWORK 1 WILL NOT COMMUNICATE WITH NETWORK 2